Suppose an array of length `n` sorted in ascending order is **rotated** between `1` and `n` times. For example, the array `nums = [0,1,2,4,5,6,7]` might become:
- `[4,5,6,7,0,1,2]` if it was rotated `4` times.
- `[0,1,2,4,5,6,7]` if it was rotated `7` times.
Notice that **rotating** an array `[a[0], a[1], a[2], ..., a[n-1]]` 1 time results in the array `[a[n-1], a[0], a[1], a[2], ..., a[n-2]]`.
Given the sorted rotated array `nums` of **unique** elements, return *the minimum element of this array*.
You must write an algorithm that runs in `O(log n)` time.
Examples
Example 1
Input:
nums = [3,4,5,1,2]Output:
1The original array was [1,2,3,4,5] rotated 3 times.
Example 2
Input:
nums = [4,5,6,7,0,1,2]Output:
0The original array was [0,1,2,4,5,6,7] and it was rotated 4 times.
Example 3
Input:
nums = [11,13,15,17]Output:
11The original array was [11,13,15,17] and it was rotated 4 times.
Constraints
- •
n == nums.length - •
1 <= n <= 5000 - •
-5000 <= nums[i] <= 5000 - •
All the integers of nums are unique. - •
nums is sorted and rotated between 1 and n times.
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