Given a binary search tree (BST), find the lowest common ancestor (LCA) node of two given nodes in the BST.
According to the [definition of LCA on Wikipedia](https://en.wikipedia.org/wiki/Lowest_common_ancestor): "The lowest common ancestor is defined between two nodes `p` and `q` as the lowest node in `T` that has both `p` and `q` as descendants (where we allow **a node to be a descendant of itself**)."
Examples
Example 1
Input:
root = [6,2,8,0,4,7,9,null,null,3,5], p = 2, q = 8Output:
6The LCA of nodes 2 and 8 is 6.
Example 2
Input:
root = [6,2,8,0,4,7,9,null,null,3,5], p = 2, q = 4Output:
2The LCA of nodes 2 and 4 is 2, since a node can be a descendant of itself according to the LCA definition.
Example 3
Input:
root = [2,1], p = 2, q = 1Output:
2Constraints
- •
The number of nodes in the tree is in the range [2, 10^5]. - •
-10^9 <= Node.val <= 10^9 - •
All Node.val are unique. - •
p != q - •
p and q will exist in the BST.
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