#33

Search in Rotated Sorted Array

Medium
ArrayBinary Search

There is an integer array `nums` sorted in ascending order (with **distinct** values).

Prior to being passed to your function, `nums` is **possibly rotated** at an unknown pivot index `k` (`1 <= k < nums.length`) such that the resulting array is `[nums[k], nums[k+1], ..., nums[n-1], nums[0], nums[1], ..., nums[k-1]]` (0-indexed). For example, `[0,1,2,4,5,6,7]` might be rotated at pivot index `3` and become `[4,5,6,7,0,1,2]`.

Given the array `nums` after the possible rotation and an integer `target`, return *the index of `target` if it is in `nums`, or `-1` if it is not in `nums`*.

You must write an algorithm with `O(log n)` runtime complexity.

Examples

Example 1
Input: nums = [4,5,6,7,0,1,2], target = 0
Output: 4
Example 2
Input: nums = [4,5,6,7,0,1,2], target = 3
Output: -1
Example 3
Input: nums = [1], target = 0
Output: -1

Constraints

  • 1 <= nums.length <= 5000
  • -10^4 <= nums[i] <= 10^4
  • All values of nums are unique.
  • nums is an ascending array that is possibly rotated.
  • -10^4 <= target <= 10^4
Code Editor